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How do I access Android View member variables without reflection?

I have a ListView that I want to be only editable (add, remove, etc.) when clicked. The functionality I want is similar to the functioning of the submit button in a form. The ListView is created within a layout file (xml). I want the user to click the ListView and it will know whether or not the ListView has been clicked.
So the ListView has a public boolean variable.
I want to set the ListView to not be editable when this variable is false. I’ve looked around online but found little information on how to go about this.
I have seen methods of implementing this using reflection. (The example code just loads the xml and checks the boolean.)
I don’t know much about Java programming, but this was the best way I could come up with to explain my problem.

A:

It is better to override setEnabled() and then call the superclass method instead of using reflection.
e.g.
MyClass.setEnabled(false)

will correctly behave as you are asking.

A:

You can use reflection to modify the value of the variable (or whatever object it is), but reflection is a lot of work.
That said, is your ListView really public? If not, you should make it protected.

Q:

How can

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Reinstall and Reactivate

System does not reactivate.

Process info

This program loads a process and then tells me what it is. According to task manager, process msi, 14, is not installed or run in current user. The same process appears several times, the highest one is 5.32

I believe there is a problem with the product as installing and using it is an interesting story. After a few seconds, the screen goes blank and the background remains but everything else is completely frozen. I tried to attach process msi, 14, to a custom process, still no luck.

If anyone has any ideas I will appreciate any help that will be greatly appreciated. thank you.

A:

I uninstalled the program and was able to activate without the crack.
Credit to Web Sheriff for the solution.

Q:

How to get the Levenshtein distance between two strings in numpy?

I have a string as follows:
s = “c&a&d#e&f#g&h”

I want to calculate the Levenshtein distance between two strings and then, if the distance is 1, I want to print out the two words. For example:
print(“c&a&d#e&f#g&h”)
print(“&c&a&d#e&f#g&h”)

This is the code that I have so far:
import numpy as np

s1 = “c&a&d#e&f#g&h”
s2 = “&c&a&d#e&f#g&h”

base = np.lexsort(s1.split(“&”))
short = s1.split(“&”)

print(sum(s1 == base[i] for i in base))